1. Calculate the kinetic energy gained. Answer in units of J.
2. Through how large a potential difference did the object fall? Answer in units of V.An object with a charge 4 C and a mass 0,5 kg accelerates from rest to a speed of 21 m/s.?
kinetic energy
W=muu/2=0.5x21x21/2 joule
conservation of energy
QU=muu/2
U=muu/2Q=0.5x21x21/2x4 VoltAn object with a charge 4 C and a mass 0,5 kg accelerates from rest to a speed of 21 m/s.?
KE = 1/2 M V^2
KE = .5 x .5kg x 21m/s^2 = 110J
Volts = J/C
V = 110J / 4C = 27.5 volts
No comments:
Post a Comment