If an object has no acceleration is it safe to say that no forces are acting upon it?

Plz help me!!!








Answers must be 3-4 sentences!! =) Thank You!!If an object has no acceleration is it safe to say that no forces are acting upon it?
rest your pencil on the table.... it isn't moving, right? it would appear no acceleration is being applied to it, and no forces are acting upon it.





but we know that's not correct.


- there is a gravitational force that is being applied to it.


- there is the upward force of the table being applied to it also so it doesn't fall.





what happens here is that the forces balance out, so there is no NET acceleration, but there are indeed many (balancing) forces acting upon the pencil...If an object has no acceleration is it safe to say that no forces are acting upon it?
No!


It has potential energy.
3 to 4 sentences? Jeez. If you are standing still you are not accelerating but you have the force of gravity pulling you keeping you on the ground. Hope that helps get you started
No, it just means the forces are in equilibrium. For example, gravity is always affecting you, but the ground is exerting an equal and opposite force called the Normal Force.

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How can you find the mass of an object?

Using a beam balance.


Or use formulaes. For eg, Mass=Volume X Density.How can you find the mass of an object?
Put it on a balance.How can you find the mass of an object?
It's easy, just use the formula mass/volume!
well you look to the lower half of the body..usually situated on the lower back..they are 2 mounds of flesh...ohhhhh mass
V (over) D

Looking for a fish game - kind of hidden object game?

I played the game before but I can't find it anymore:( It was where you go down in the ocean and the timer is your air tank I think. You have to take pictures of certain kinds of fish to get points.Looking for a fish game - kind of hidden object game?
Oddly, I don't remember the name and yet I know where the game is, lol. It's on http://www.bigfishgames.com/





I did a trial download of the game from that site (a site I have used and trusted for nearly three years) but didn't buy the game. I'm sorry I can't recall the name. If you like Hidden Objects games, as I do, the best I've found is the Mystery Case Files series, especially their Prime Suspects game. (They also have Huntsville Alabama, Ravenhearst, and I believe a fourth one that I didn't like as much. I far preferred Prime Suspects and Ravenhearst.)

If you double the weight of an object, will it's acceleration be twice as large or half as large?

This is in the absence of friction and other forces.... thanks in advance.If you double the weight of an object, will it's acceleration be twice as large or half as large?
weight = mg





F = ma


mg = ma


a = mg / m = g





for weight = 2mg


F = ma


2mg = ma


a = 2mg / m = 2g





2g is 2 times greater than g, so it doubles the acceleration.





Note, this is only true if you double the g constant, not the mass, because the mass cancels when solving for a. You can see this easily, if you drop a 1 pound ball and a 2 pound ball, both accelerate at the same rate. If you were to drop a 1 pound ball on the moon and on the Earth, you would see the ball accelerates more quickly on the Earth because g for earth = 9.8 and g for the moon = 9.8/6If you double the weight of an object, will it's acceleration be twice as large or half as large?
Your question is not clear. If you are dropping a two pound weight and a four pound weight, the acceleration will be the same. In this case the force is not fixed.





If by weight, you mean mass, and your force is constant, then the acceleration will be cut in half.





If the weight is doubled by doubling gravity, then the acceleration will double.





Is there a chance you are confusing 'weight' and 'mass'?
I believe F = MA would be the equation to use. Assuming that the force stayed constant, the acceleration would be half as much if the mass doubled.





Solving for A, A = F/M , so, If the new mass was twice the old mass, the new acceleration would be half.

An object moving a 30 m/s to the right begins to accelerate at 5 m/s^2 to the left for 3 seconds.?

Then the question is. What is (a) the displacement and (b) the velocity of the object after 3 seconds? (Include direction in your answer.)





I need help on this physics question because my physics teacher isn't really good at teaching us haha. Well please help and thank you.An object moving a 30 m/s to the right begins to accelerate at 5 m/s^2 to the left for 3 seconds.?
If your object is moving to the right and it undergoes an acceleration to the left, this is a negative acceleration - the car is slowing down. Using basic motion equations we can solve this problem. Let's identify what variables we need that the question gives us:





Acceleration = - 5 m/s^2


Time = 3 s


Initial velocity = 30 m/s [right]


Final velocity = ?


Displacement = ?





For a), we need to solve for displacement.


Displacement = (initial velocity)(time) + 0.5(acceleration)(time)^2


= (30 m/s [right])(3 s) + 0.5(- 5 m/s^2[right])(3 s)^2


= 90 m [right] + (-22.5 [right])


= 67.5 m





For b), we need to solve for the final velocity after it has travelled this far.





final velocity^2 = (initial velocity)^2 + 2(acceleration)(displacement)


= SQRT (30 m/s [right])^2 + 2(- 5 m/s^2[right])(67.5 m)


= SQRT (900 m/s [right] + (- 337.5 m/s [right])


= SQRT 562.5 m/s [right]


final velocity = 23.72 m/s [right]





The SQRT mean you must take the square root of whatever your answer in brackets is since the variable we are solving for is squared.


These equations are given to you in grade 11 I believe - it's best to memorize 'em!

An object is thrown vertically into the air?

An object is thrown vertically into the air. Because of air resistance, the time for its descent will be:





longer than the ascent time.


shorter than the ascent time.


equal to the ascent time.


not enough information given to sayAn object is thrown vertically into the air?
equal to the ascent time.An object is thrown vertically into the air?
In general the descent time will be longer. When the object is launched at some speed v it is slowed down by gravity and air resistance. When it stops at its highest point and begins to fall gravity works to speed it up while air resistance fights to slow it down.





Thus on the way up both are working to slow it down (maybe it slow down and stop quickly). On the way down the two fight each other and the object accelerates slower (thus taking longer to return to the surface).





I hope that helps!

An object with a charge 4 C and a mass 0,5 kg accelerates from rest to a speed of 21 m/s.?

An object with a charge 4 C and a mass 0,5 kg accelerates from rest to a speed of 21 m/s.





1. Calculate the kinetic energy gained. Answer in units of J.





2. Through how large a potential difference did the object fall? Answer in units of V.An object with a charge 4 C and a mass 0,5 kg accelerates from rest to a speed of 21 m/s.?
kinetic energy


W=muu/2=0.5x21x21/2 joule


conservation of energy


QU=muu/2


U=muu/2Q=0.5x21x21/2x4 VoltAn object with a charge 4 C and a mass 0,5 kg accelerates from rest to a speed of 21 m/s.?
KE = 1/2 M V^2


KE = .5 x .5kg x 21m/s^2 = 110J


Volts = J/C


V = 110J / 4C = 27.5 volts

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