A diverging lens is used to form a virtual image of an object. The object is 76.0 cm in front of the lens, and

the image is 38.0 cm in front of the lens. Determine the focal length of the lens.A diverging lens is used to form a virtual image of an object. The object is 76.0 cm in front of the lens, and
1/o + 1/i = 1/f





f = i*o / (i+o)





They give you object distance (o) and image distance (i). An image in front of the lens is taken to be negative. Plugnchug to get f, which will also be negative.A diverging lens is used to form a virtual image of an object. The object is 76.0 cm in front of the lens, and
f = - 76 cm. p = 1 / 76, q = - 2 / 76, therefore f = - 1 / 76. Just be careful with the signs. The focal length of a diverging lens is negative, and its virtual image is always in front of the lens, so the image distance is negative.

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