Given the weight of an object and the height from which it is dropped, can I calculate the impact velocity.?

I assume no air friction.


I am trying to understand impact velocity and force......Given the weight of an object and the height from which it is dropped, can I calculate the impact velocity.?
The weight doesn't matter. Since we're neglecting air resistance, all objects fall the same. You can just use conservation of energy to calculate the velocity.





Initial potential energy = mgh


=


Final kinetic energy = 1/2 mv^2





Solve for velocity (as promised, masses cancel):


v = sqrt (2gh)





So if you know height, and you know the acceleration due to gravity (9.8 m/s^2 at earth's surface), you can plugnchug to get the speed at impact.Given the weight of an object and the height from which it is dropped, can I calculate the impact velocity.?
The weight makes no difference. g equals 32 feet per second per second. If you drop an object from 1000 feet high, Divide 1000 by 16, this is the distance the object will fall in the first second, you get 62.5. Find the square root of this number, it is 7.90, this is the time, in seconds that the object will fall. Multiply this by 32, you get 252,98, this is the velocity in feet per second that the object hits the ground. You can easily convert this into MPH by dividing 252,98 by 88, the distance in feet that an object travels in one second if it is moving at 60MPH, you get 2,874, multiply this by 60 and you get 172.5 MPH.
Potential Energy (PE) = mgh = Mass(kg) x 9.81m/s虏 x h (m)


This will give you PE in Joules (J).


As Energy cannot be created or destroyed, on falling and accelerating, the PE converts to Kinetic Energy (KE).


(Same as PE in Joules).





The impact velocity (v) will be, v = 鈭?KE/m.


(i.e. The square root of (2 x Ke) 梅 mass (kg).


The answer will be in metres per second (m/s)
something of mass 10Newtons falls to earth a speed of 10m/s 1N = 100grams


then you have the distance travelled and the speed of it at impact