Sunday, December 27, 2009

The distance that a free falling object falls is directly proportional to the square of the time it falls.?

If an object fell 81 feet in 4 seconds, how far will it have fallen by the end of 7 seconds?The distance that a free falling object falls is directly proportional to the square of the time it falls.?
Distance that it will have fallen by the end of 7 seconds.


= u*t+0.5*at^2


= [0*t+0.5*10*(7^2)] feet


= 245 feet





This means it will travels an additional distance of (245-81)feet = 164 feet between 4 seconds and 7 seconds.The distance that a free falling object falls is directly proportional to the square of the time it falls.?
Sure, at the outset you need to select any various seconds

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